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Answer 238 g of uranium contains NA particles = 6.02 x 1023 238 / (6.02 x 1023) g of uranium contains 1 particle therefore 238 x 1014 / (6.02 x 1023) g of uranium contains 1014 particles 100,000,000,000,000 particles! = 3.95 x 10-8g of uranium (39.5 ng of Uranium)
Just think what a tiny dust particle that would be…. yet it would contain 1014 uranium atoms! |
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Cyberphysics - a web-based teaching aid - for students of physics, their teachers and parents....
